C++ Program to convert Decimal to Binary
We can convert any decimal number (base-10 (0 to 9)) into binary number (base-2 (0 or 1)) by C++ program.
Decimal Number
Decimal number is a base 10 number because it ranges from 0 to 9, there are total 10 digits between 0 to 9. Any combination of digits is decimal number such as 223, 585, 192, 0, 7 etc.
Binary Number
Binary number is a base 2 number because it is either 0 or 1. Any combination of 0 and 1 is binary number such as 1001, 101, 11111, 101010 etc.
Let's see the some binary numbers for the decimal number.
Decimal | Binary |
---|---|
1 | 0 |
2 | 10 |
3 | 11 |
4 | 100 |
5 | 101 |
6 | 110 |
7 | 111 |
8 | 1000 |
9 | 1001 |
10 | 1010 |
Decimal to Binary Conversion Algorithm
Step 1: Divide the number by 2 through % (modulus operator) and store the remainder in array
Step 2: Divide the number by 2 through / (division operator)
Step 3: Repeat the step 2 until the number is greater than zero
Let's see the C++ example to convert decimal to binary.
- #include <iostream.h>
- #include <conio.h>
- void main()
- {
- int a[10], n, i;
- cout<<"Enter the number to convert: ";
- cin>>n;
- for(i=0; n>0; i++)
- {
- a[i]=n%2;
- n= n/2;
- }
- cout<<"Binary of the given number= ";
- for(i=i-1 ;i>=0 ;i--)
- {
- cout<<a[i];
- }
- getch();
- }
Output:
Enter the number to convert: 9 Binary of the given number= 1001
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